例1
代码如下
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30create function f_split(@SourceSql varchar (8000),@StrSeprate varchar (10))
returns @ temp table (a varchar (100))
--实现split功能 的函数
--date :2003-10-14
as
begin
declare @i int
set @SourceSql=rtrim(ltrim(@SourceSql))
set @i=charindex(@StrSeprate,@SourceSql)
while @i>=1
begin
insert @ temp values ( left (@SourceSql,@i-1))
set @SourceSql= substring (@SourceSql,@i+1,len(@SourceSql)[email protected])
set @i=charindex(@StrSeprate,@SourceSql)
end
if @SourceSql<> ‘‘
insert @ temp values (@SourceSql)
return
end
select * from dbo.f_split( ‘1,2,3,4‘ , ‘,‘ )
a
--------------------
1
2
3
4
（所影响的行数为 4 行）
例2
代码如下
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43--SQL Server Split函数
--Author:zc_0101
--说明：
--支持分割符多字节
--使用方法
--Select * FROM DBO.F_SQLSERVER_SPLIT(‘1203401230105045‘,‘0‘)
--select * from DBO.F_SQLSERVER_SPLIT(‘abc1234a12348991234‘,‘1234‘)
--Select * from DBO.F_SQLSERVER_SPLIT(‘ABC‘,‘,‘)
CREATE FUNCTION F_SQLSERVER_SPLIT(@Long_str varchar (8000),@split_str varchar (100))
RETURNS @tmp TABLE (
ID inT IDENTITY PRIMARY KEY ,
short_str varchar (8000)
)
AS
BEGIN
DECLARE @long_str_Tmp varchar (8000),@short_str varchar (8000),@split_str_length int
SET @split_str_length = LEN(@split_str)
IF CHARINDEX(@split_str,@Long_str)=1
SET @long_str_Tmp= SUBSTRING (@Long_str,@split_str_length+1,LEN(@Long_str)[email protected]_str_length)
ELSE
SET @[email protected]_str
IF CHARINDEX(REVERSE(@split_str),REVERSE(@long_str_Tmp))>1
SET @[email protected][email protected]_str
ELSE
SET @[email protected]_str_Tmp
IF CHARINDEX(@split_str,@long_str_Tmp)=0
Insert INTO @tmp select @long_str_Tmp
ELSE
BEGIN
WHILE CHARINDEX(@spl(www.jb51.net)it_str,@long_str_Tmp)>0
BEGIN
SET @short_str= SUBSTRING (@long_str_Tmp,1,CHARINDEX(@split_str,@long_str_Tmp)-1)
DECLARE @long_str_Tmp_LEN INT ,@split_str_Position_END int
SET @long_str_Tmp_LEN = LEN(@long_str_Tmp)
SET @split_str_Position_END = LEN(@short_str)[email protected]_str_length
SET @long_str_Tmp=REVERSE( SUBSTRING (REVERSE(@long_str_Tmp),1,@[email protected]_str_Position_END))
IF @short_str<> ‘‘ Insert INTO @tmp select @short_str
END
END
RETURN
END
例3
Sql2000andSql2005实用的Split函数
代码如下
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48sql2000
CREATE FUNCTION [dbo].[splitstring_array]
(
@string nvarchar(4000),@split char (1)
)
RETURNS @array table
(
oneStr nvarchar(100)
)
AS
BEGIN
declare @v_code varchar (60)
--zell 2006-05-26
--set @string = replace(@string,‘ ‘,@split)
--set @string = replace(@string,‘，‘,@split)
while len(@string) > 0
begin
if charindex(@split,@string,1) != 0
begin
set @v_code = substring (@string,1,charindex(@split,@string,1)-1)
set @string = substring (@string,charindex(@split,@string,1)+1,len(@string))
end
else if charindex(@split,@string,1) = 0
begin
set @v_code = @string
set @string = ‘‘
end
insert into @array(onestr) values (@v_code)
end
RETURN
END
sql2005
CREATE function [dbo].[func_splitid]
(@str varchar ( max ),@split varchar (10))
RETURNS @t Table (c1 nvarchar(100))
AS
BEGIN
DECLARE @x XML
SET @x = CONVERT (XML, ‘<items><item /><item /></items>‘ )
INSERT INTO @t SELECT x.item.value( ‘@id[1]‘ , ‘nvarchar(100)‘ ) FROM @x.nodes( ‘//items/item‘ ) AS x(item)
RETURN
END
以上这篇SQL中实现SPLIT函数几种方法总结
